# Line slope calculator 3x+4y=34

**Straight line given by points A[6; 4] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+8.5

**Canonical form of the line equation:**3x+4y-34 = 0

**Parametric form of the line equation:**

x = 4t+6

y = -3t+4 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 11.3333

**Y intercept:**y

_{0}= q = 8.5

**Distance line from the origin:**d

_{0}= 6.8

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[8; 2.5]

**Perpendicular Bisector equation:**4x-3y-24.5 = 0

**Vector OA = (6; 4) ; |OA| = 7.2111**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 64**

**Angle ∠ AOB = 27°58'46″ = 0.4883 rad**